Grade 10 Answers Grade 10 Answers$3280.00 + ($452)4 + $693.00 = $5781.00 $5781.00/$7.00 = 825.85 Therefore 826 fares are necessary to have enough money
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43 shoes / (3)^.5/2 = 86 shoes / (3)^.5 per hour 86/(3)^.5 * 8 = 397.2 Therefore 397 shoes could be made in a day
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[$750 - (216 + 100 + 40 + 329 - 5)] 3/2 = $90.00
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A) 26 = 1/2(4/3 b)(1/2 b) 26 = 4/12 b 26(12)/4 = b b = 78 B) 1/3b = a a=1/2(6+18)(9) b = 3(6)=18 =108 h = (1/2b)=9
Answer:
t dist 1s 5m 2s 7.5m 3s 11.25m 4s 16.875m 5s 25.313m 6s 37.97m 6-5 = 37.97 - 25.313 1s = 12.66m need to go 30-25.313 = 4.687 x = 4.687m/12.66m/s = 0.37s 5s+0.37s = 5 37/100 seconds
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720 degrees/sec x 60s/min x 1 revolution/360 degrees = 120 rev/min.
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(x+5) + 1/2(x+5)+2+3[1/2(x+5)+2] = 5000 x+5 + 1/2x + 45 + 3/2x + 7.5 + 6 = 5000 3x + 23 = 5000 x = 5000-23/3 = 1659
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We know that multiplication by an even number makes an odd number even so y+8 and 20x-16 are even we need y^2 and x^2 to be odd. y=x^2 4y+8 = 20x-16 4x^2 - 20x +24 = 0 x^2 - 5x + 6 = 0 (x-2)(x-3) = 0 x = 2, x = 3 x^2 = 4 or x^2 = 9 Therefore y = 9 Perimeter = x^2 + 4y + 8 + y + 20x - 16 = 9 = 36 + 8 + 9 + 60 - 16 = 106
Answer:
40km/h x h/60min = 2/3km/min (150revs/min) (x km/rev) = 2/3km/min 150x = 2/3km/min x km = 2/450 = 0.0044 x = 4.44 meters
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92 = 4(x+8)+8(x)=12x+32=92 12x = 60 x = 5 (x+8)(x+4) = A(DEFG) (13) (9) = 117
Answer:
BD (1/3 a + 1/2 a) (5/6 a) 5 -- = ------------------- = -------- = --- AD (a + 1/3 a + 1/2 a) (11/6 a) 11
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(-2+x^2)^5 = 1 (-2 + x^2) = 1^ 1/5 (-2 + x^2) = 1 x^2 = 3 x = +/- (3)^.5 in +(3)^.5 ????? + Q
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2(x+9+x+x+3)+x+4 = 77 2x+18 + 2x + 2x +6 + x+4 = 77 7x+28 =77 7x = 49 x = 7 Therefore x+9 = 16 x = 7 x+3 = 10 x+4 = 11 16^2 = 7^2+h^2 h=14.39 A = 1/2(2x+x+4)(14.39) = 179.84 A sect + (x+3)(x+4) = (10)(11) = 110 Therefore A total = 179.84 + 110 = 289.84
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The time required to retrieve the life jacket is the time the jacket floated. t=40min + t. t1 = time for boat to go 3km = d/v = 3km/50km/hr = 0.06hrs (40min * 1hr)/60min = 2/3 hrs tt = total time R^.5 = d/tt = 3km/(2/3 + 0.06) = 4.13 km/hr
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Digit ABC Such that a+b+c = 15 2b+b = 15 a > b+c and a-b = b-c b = 5 10-c > b+c a = 2b-c a+c = 10 10-b > 2c a = 10-c 5 > 2c 2.5 > c c must be odd, therefore c=1, b=5, c=1, a=9 951 = abc 9 > 5+1 9+5+1 = 15 9-5 = 5-1 4 = 4
Answer:
(x+5)(x+3) = x^2+3x+5x+5 = x^2+8x+15
Answer:
5/x+5 = x+5/a a = (x+5)^2/5 A = 1/2(x+5)(x+5)^2/5 = (x+5)(x^2+10x+25)/10 = x^3+10x^2+25x+5x^2+50x+125/10 = x^3+15x^2+75x+125/10 = 0.1x^3+1.5x^2+7.5x+125
Answer:
CURRENT TIME 5:00 - x 5:00-(x+40) = 2:00+4x = 5:00 - 28min 4:60-40-x = 2:00=4x = 4:32 4:20 = 2:00 = 5x 2:20 = 5x 140min = 5x x = 28 min Check 5:00 - (68 min) = 2:00 + 4(28 min) 3:52 = 3:52
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1/2(ah)+h(a+b)/2 + 1/2(bh) = 126 3h + 7h + 4h = 126 14h = 126 h=9 c^2 = a^2+h^2 d^2=b^2+h^2 c = (36 + 81)^.5 d = (64 + 81)^.5 = 10.82 = 12.04 Therefore c + (a+b)/2 + d + b + (a+b)/2 + a = P 10.82 + 7 + 12.04 + 8 + 7 + 6 = P 50.86 = P
Answer:
Let x = cost of the ring. 3/4(2x) = 159.99 x = $106.66 3/4(2x) - 0.20(3/4(2x)-x) = profit 159.99 - 0.20(159.99) - $106.66 = $21.232
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$80,000 = 5(x-1/4x) = 5(3/4x) $80,000 = 15x/4 $320000/15 = x $21333.33 = x Mary's savings = 5(Mary's salary) - Mary's spending = 5(2(21333.33)-1/3x(2(21333.33))) = $142222.22
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Let s = sandwich cost c = coffee d = donut -(3s+7c+d) = -3.15 3s+7c+d = 3.15 4s+10c+d = 4.20 3.15 - 9c +7c + d = 3.15 ------------------- 1s+3c+0 = 1.05 -2c+d = 0 1s = 1.05 - 3c d = 2c 1s+1c+1d = 1.05 - 3c +1c +2c = 1.05
Answer:
x/10 + 20x/4 = x/5 + (20-x)/12 6x + 15(20-x) = 12x + 5(20-x) 12(20) - 15x = 6x + 5(20) - 5x 300 - 100 = x + 15x 200 = 16x x = 12.5km = distance Shawn should ride.
Answer:
y = # of marbles child 1 has. x = # marbles 1/2x - 4 = y 6 + 1/5x + 1/2x - 4 + 1/3(y) + 1/3(y) - 1 = x 6 + 1/5x + 1/2x - 4 + 1/3(1/2x - 4) + 1/3(1/2x-4) - 1 = x -1.67 = -0.033x x = 50 Therefore child (1) 1/2(50-4) = 21 (2) 6+1/5 (50) = 16 (3) 1/3(y) = 7 (4) 1/3(y)-1=6
Answer:
Area ABC = 1/2 base x height a=2b = 1/2 (2a) (b(b+a))^.5 = 1/2 (2a) (1/2 a(3/2 a))^.5 = 1/2 (2a) (3/4 a^2)^.5 = 1/2 (2a) (3^.5/2 a) = 3^.5/2 a^2 Area DEC = 1/2 (2b) (3/4 b^2)^.5 = 3^.5/2 b^2 Triangle ABC 3^.5/2 a^2 a^2 4 ------------ = ---------- = ------- = --- Triangle DEC 3^.5/2 b^2 1/4 a^2 1 Triangle ABC has an area 4 times greater than traingle DEC.
Answer:
h/sin 30 = 2/sin 90 h/0.5 = 2/1 h = 1 Ap = 2(1) = 2 Asector = 30/360 pir^2 = 4pi / 12 = 1.047 Shaded area = 2 - 1.047 = 0.9528
Answer:
h^2 = (100)^2 + y^2 10144m^2 = 10000m^2 + y^2 y = 2/3x y^2 = 144m^2 y = 12m 12(3/2) = x = 18
Answer:
(1/2 a)^2 + g^2 = c^2 (1/2 d)^2 + h^2 = b^2 g^2 = c^2 - (1/2 a)^2 h^2 = (b^2) - (1/2 d)^2 g = [4 - (3^.5)^2]^.5 h = (7 - 3/4)^2 = 1 h = [(28 - 3)/4]^.5 h = 5/2 g + h = 3 1/2
Answer:
If CE = CD , triangle is isosceles, therefore angle DEC = angle EDC = 40 degrees angle BDC = angle GDE = 90 degrees Therefore, angle BDG = 360 - (2(90 degrees) + 40 degrees) = 140 degrees.
Answer:
line AC = [(x2 - x1)^2 + (y2 - y1)^2] ^.5 = [49 + 0] ^.5 = 7 h = [(x2 - x1)^2 + (y2 - y1)^2]^.5 h = [0 + 4^2]^.5 = 4 Area = 1/2bxh = 1/2(7x4) = 14
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Since a line perpendicular to a line of slope zero will be parallel to the y-axis by putting the value of 1/2 r = x into the equation of the circle we can find the coordinates of the chord end points and so find the length. 1/2 r = x = 2 l = [(x2 - x1)^2 + (y2 - y1)^2]^.5 x^2 + y^2 = r^2 = [0 + (2(12)^.5)^2] y^2 = 16 - 4 = [4(12)]^.5 y = +/- (12)^.5 = (48)^.5
Answer:
NONE???
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Distance from A to X covered in 3s at a rate of 1m/s therefore, y = 3s(1m/s) y = 3m Need BA to get total distance tan 60 degrees = line BA/6m line BA = 10.39m Therefore BX = total distance = 10.39m+3m = 13.39m
Answer:
The area of Triangle ADC=8=.5*x^2 8*2=x^2 4=x,therefore AD=DC(in length) Area of triangle BDC=3=.5*(x)*(y) 3*2=4*y y=1.5 We know EB is parallel to DC, AB is parallel to BC so AD-BC=AE 4-a.5=AE 2.5=AE also EB=DC=AD=4 so the area of triangle AEB=.5*(EB)(AE) .5(4)(2.5) 5
Answer:
Area of square = sxs=2rx2r=4r^2 Area of 4 triangles = 4(1/2(1/3s)x(1/3s))=2(2/3r)^2=8/9???? Area of circle = Area Square - Area triangle =4r^2-8/9r^2 =28/9r^2=3.111r^2 r=2 =28/9(4)=12.444 NOTE: pi is approximately 3.111
Answer:
5(6.4) + 4(6.5) +9/10 = 6.7
Answer:
A+B/2 = 50 B+C/2=75 C+D?@+&) A+B =100 B=150-C C+D=140 A+D+10=100 B=150-C C=140-D A+D = 90 B=150-140+D C=140-D A+D/2=45 B=10+D
Answer:
Volume = 1/2bh(l) = 1/2(3x)(4x)(10x) = 60x^3 202.5 = 60x^3 x^3 = 3.375 x = 1.5
Answer:
Bread Juice (1) 1066 48 Price of bread (2) 988 56 Price of juice (1066 48) (.015) = (1066(0.015)+48(0.00)) ( 988 56) ( .99) ((9.88(0.015)+56(0.99)) = (63.51) (70.26) It will cost $63.51 to run cafe number 1 $70.26 to run cafe number 2.
Answer:
(x-2 + 4(3)^.5)(x-2 - 4(3)^.5) = x^2 - 4x + (2-4(3)^.5)(2+4(3)^.5) = x^2 - 4x + 4 - 16(3) = x^2 - 4x - 44
Answer:
x = teachers y = professors 40 = 35x + 50y/x+y 40x + 40y = 35x + 50y 5x = 10y Y = 1/2X If y = 1 x = 2 Therefore teachers : professors 2 : 1
Answer: 
Y = 0 Y = (X+2)(X-3) Y = Y 0 = (X+2)(X-3) 0 = X+2 X-3 = 0 X = -2 X = 3 Line AB = [(x2-x1)^2 + (y2-y1)^2]^.5 = [5^2 + 10^2]^.5 = 5