Proton NMR, Sample #9


Analysis: C10H14O
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C10H14O

From the molecular formula, the compound has "4 degrees of unsaturation" (four double bonds or rings), suggesting the presence of an aromatic compound (benzene has four degrees of unsaturation).

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The proton NMR has four sets of peaks; a singlet at 3.6 (3H), two sets of doublets centered around 6.9 (4H), a septet at 2.7 (1H) and a doublet at 1.6. The singlet at 3.6 is consistent with an isolated CH3 adjacent to an electronegative center, such as an oxygen. The septet and doublet strongly suggest an isopropyl group CH(CH3) 2 in which the carbon is bonded to something mildly electronegative and the two doublets centered at 6.9 strongly suggest a 1,4-disubstituted aromatic compound.

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Structure: structure

IUPAC Name: 4-isopropyl-1-methoxybenzene (4-(1-methylethyl)-1-methoxybenzene)

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Copyright 1996, Paul R. Young, University of Illinois at Chicago, All Rights Reserved