Lecture #4 – Dijsktra¶
Lecture notes¶
Slides: Lecture 4
- Related research articles:
Code examples: Google colab
Code¶
The code used during the lecture will be available after the lecture.
Problem definition¶
A problem can be defined like this:
class Problem(object):
"""The abstract class for a formal problem. A new domain subclasses this,
overriding `actions` and `results`, and perhaps other methods.
The default heuristic is 0 and the default action cost is 1 for all states.
When yiou create an instance of a subclass, specify `initial`, and `goal` states
(or give an `is_goal` method) and perhaps other keyword args for the subclass."""
def __init__(self, initial=None, goal=None, **kwds):
self.__dict__.update(initial=initial, goal=goal, **kwds)
def actions(self, state): raise NotImplementedError
def result(self, state, action): raise NotImplementedError
def is_goal(self, state): return state == self.goal
def action_cost(self, s, a, s1): return 1
def h(self, node): return 0
def __str__(self):
return '{}({!r}, {!r})'.format(
type(self).__name__, self.initial, self.goal)
We also need to represent a node and different functions:
class Node:
"A Node in a search tree."
def __init__(self, state, parent=None, action=None, path_cost=0):
self.__dict__.update(state=state, parent=parent, action=action, path_cost=path_cost)
def __repr__(self): return '<{}>'.format(self.state)
def __len__(self): return 0 if self.parent is None else (1 + len(self.parent))
def __lt__(self, other): return self.path_cost < other.path_cost
failure = Node('failure', path_cost=math.inf) # Indicates an algorithm couldn't find a solution.
cutoff = Node('cutoff', path_cost=math.inf) # Indicates iterative deepening search was cut off.
def expand(problem, node):
"Expand a node, generating the children nodes."
s = node.state
for action in problem.actions(s):
s1 = problem.result(s, action)
cost = node.path_cost + problem.action_cost(s, action, s1)
yield Node(s1, node, action, cost)
def path_actions(node):
"The sequence of actions to get to this node."
if node.parent is None:
return []
return path_actions(node.parent) + [node.action]
def path_states(node):
"The sequence of states to get to this node."
if node in (cutoff, failure, None):
return []
return path_states(node.parent) + [node.state]
Queue¶
Each algorithm doesn’t use the same type of queue/list. To make surethat we have the data structure that we need we can create our own.
FIFOQueue = deque
LIFOQueue = list
class PriorityQueue:
"""A queue in which the item with minimum f(item) is always popped first."""
def __init__(self, items=(), key=lambda x: x):
self.key = key
self.items = [] # a heap of (score, item) pairs
for item in items:
self.add(item)
def add(self, item):
"""Add item to the queuez."""
pair = (self.key(item), item)
heapq.heappush(self.items, pair)
def pop(self):
"""Pop and return the item with min f(item) value."""
return heapq.heappop(self.items)[1]
def top(self): return self.items[0][1]
def __len__(self): return len(self.items)
Route Problem¶
In a RouteProblem, the states are names of “cities” (or other locations), like ‘A’. The actions are also city names; ‘Z’ is the action to move to city ‘Z’. The layout of cities is given by a separate data structure, a Map, which is a graph where there are vertexes (cities), links between vertexes, distances (costs) of those links (if not specified, the default is 1 for every link), and optionally the 2D (x, y) location of each city can be specified. A RouteProblem takes this Map as input and allows actions to move between linked cities.
class RouteProblem(Problem):
"""A problem to find a route between locations on a `Map`.
Create a problem with RouteProblem(start, goal, map=Map(...)}).
States are the vertexes in the Map graph; actions are destination states."""
def actions(self, state):
"""The places neighboring `state`."""
return self.map.neighbors[state]
def result(self, state, action):
"""Go to the `action` place, if the map says that is possible."""
return action if action in self.map.neighbors[state] else state
def action_cost(self, s, action, s1):
"""The distance (cost) to go from s to s1."""
return self.map.distances[s, s1]
We also need to represent the Map of the problem.
class Map:
"""A map of places in a 2D world: a graph with vertexes and links between them.
In `Map(links, locations)`, `links` can be either [(v1, v2)...] pairs,
or a {(v1, v2): distance...} dict. Optional `locations` can be {v1: (x, y)}
If `directed=False` then for every (v1, v2) link, we add a (v2, v1) link."""
def __init__(self, links, locations=None, directed=False):
if not hasattr(links, 'items'): # Distances are 1 by default
links = {link: 1 for link in links}
if not directed:
for (v1, v2) in list(links):
links[v2, v1] = links[v1, v2]
self.distances = links
self.neighbors = multimap(links)
self.locations = locations or defaultdict(lambda: (0, 0))
def multimap(pairs) -> dict:
"Given (key, val) pairs, make a dict of {key: [val,...]}."
result = defaultdict(list)
for key, val in pairs:
result[key].append(val)
return result